p. 2, line 3: . . . and we **s**ay . . .

p. 9, Fig. DE1.3: the current through *R* is 1 mA directed down

p. 9, 2nd papragraph: . . . Fig. 1.2**0** . . .

p. 9, 2nd paragraph, second line: . . . a positive resistance, o**f**
course) . . .

p. 48, Prob. 1.46: . . . change the **5**-ohm resistor to a **3**-ohm
resistor. . .

p. 54, next to last equation: *i*_{1} + *i*_{3}
- **17** = 0

p. 54, last equation: -*i*_{2} - *i*_{3} + **21**
= 0

p. 55:

| 17 -3 | del_{1}= | | | -21 5 |

p. 64, line 23: *v*_{2} = -1.5 V

p. 66, line 4: to the supe**r**node . . .

p. 69, line 6: *v*_{1} = 1.5 V

p. 99, Fig. P2.22: the voltage source should be labeled "*v*"

p. 106, numerator for second equation: 5.0 x 10^{-5} + 10.0

p. 106, last equation: . . . (10 x 10^{3})(1.0 x 10^{-3})^{2
}p. 110, 1st line: Oper**a**tional-amplifier . . .

p. 116, 1st equation: *v = R _{g}i_{g}* = .
. .

p. 123, Fig. 3.31: insert node

p. 124, last line: . . . barg

p. 128, Equation (3.11): 9

p. 129, 1st equation:

p. 138, 1st equation:

p. 150, Fig. P3.4: the op amp should be in color

p. 155, Problem 3.24: . . . Fig.

p. 157, Fig. P3.39: remove the dot directly above the voltage source

p. 162, last line: interchange the answers to (b) and (c)

p. 168, answer to Drill Exercise 4.4: (c)

p. 202, line 15: . . . cannot

p. 202, Equation (4.3):

p. 202, line 22:

p. 202, last line of text: . . . capacitor . . .

p. 203, 5th equation:

p. 203, 6th equationn:

p. 203, 9th equation: ... = -2(0) - 24 = -24 V/s

p. 206, 4th equation:

p. 207, 1st equation:

p. 207, 3rd equation:

p. 207, 5th equation:

p. 207, Drill Exercise 4.19: . . . initial con

p. 207, Drill Exercise 4.19: answers out of sequence

p. 217, Problem 4.78: replace colon with semicolon after part (b)

p. 221, line 16: . . . in

p. 224, answer to Drill Exercise 5.1: (b) -2

p. 225, line 10: . . . re

p. 256, Example 5.9, second line: . . . input

{ 2Vfor -inf <t< 0(v_{s}t) = { { 4Vfor 0 <t< inf

p. 260, Example 5.10: . . . (see Fig. 5.2**6** on p. 24**7**)
. . .

p. 265, Example 5.13, line 2: . . . input **current** . . .

p. 268, Fig.P5.8: the current *i*_{1} (and arrow) should be
in color

p. 272, Problem 5.53: **and (c) v_{o}(t).**p. 273, 1st line of Sec. 6.1: . . . init

p. 278, 7th line from bottom: . . . After . . .

p. 282, last line:

p. 292, Fig. DE6.4: change inductor value to ½ H

p. 298, Fig. 6.20: units for current scale are "mA"

p. 300, last line: replace = sign with + sign

p. 303, Drill Exercise 6.9, line 2: . . . =

p. 304, Fig. 6.23: "

p. 321, Example 7.4, line 2:

p. 321, 323, 325, Running head: . . . ZERO-I

p. 322, line 20: you can have the computer print out . . .

p. 326, line 00016 of program: I2K=I2+(-I2+V)*DELT

p. 339, Fig. DE7.10: label capacitor voltage "

p. 340, line 21: . . . correspond

p. 355, 3rd equation from bottom:

p. 356, line 3: and this result is know

p. 362, 1st equation: insert underbar

p. 362, line 5 from bottom: . . . capacitor.

p. 365, answer to Drill Exercise 8.5: (b)

p. 370, next to last equation: insert underbar

p. 382, middle answer to Drill Exer. 8.12:

p. 383, 2nd answer to Drill Exercise 8.13:

p. 389, Figs. P8.39 and P8.40: reverse polarity of lower voltage source

p. 392, last equation: insert underbar

p. 397, line 1: . . . when

p. 409, 7th equation: replace 1 in numerator with

p. 410, 6th line from bottom: the plus at the neutral wire

p. 416, Example 9.10, first line: insert underbar

p. 417, Fig. 9.25: Replace

p. 422, next to last equation: change the minus sign between the two terms to +

p. 431, 2nd line of equations: insert underbar

p. 442, equation for

p. 446, footnote: Hendrik (not Hendrick)

p. 450, Fig. 10.10(b): ang

p. 459, last equation: |

p. 467, 4th line from bottom: . . . 1/sqrt

p. 479, last paragraph: Again let

p. 490, Problem 10.4:

p. 513, 5th line from bottom: denomin.for

p. 523, 525, 527, Running head: APPLICATION TO CIRCUITS

p. 529, numerator to first answer of Drill Exercise 11.20:

p. 556, Equation (12.3): . . .

p. 562, Example 12.4, first line: . . . (p. 561

p. 567, next to last equation: . . . = (-2

p. 570, Example 12.6, line 6: the output (Th

p. 570, Drill Exercise 12.5, first line: . . . Fig. 12.1

p. 588, Problem 12.2: resonance frequency.

p. 608, answer to Drill Exercise 13.2:

p. 615, line 14: . . . the fo

p. 650 and inside back cover: replace "

p. 655, 2nd equation: . . . [6

p. 682, line 3: . . .

p. 686, line 2: are irrelev

p. 687, line 13: . . . and final time, respec

p. 691, 4th line from bottom: seven characters, L

p. 697, answer to Problem 2.17: remove the first /

p. 697, answer to Problem 2.30: 10 V, 6 V, 4 V

p. 697, answer to Problem 3.22: -2.16 A, 0.96 V

p. 698, answer to Problem 4.10, last part: 3

p. 700, answer to Problem 4.73: (d) 16

p. 700, answer to Problem 4.79: answers out of sequence

p. 701, answer to Problem 5.47: (a)

p. 701, answer to Problem 6.14: answers out of sequence

p. 701, answer to Problem 6.18: variable should be

p. 703, answer to Problem 9.16: (a) 0.5,

p. 703, answer to Problem 9.41: third angle is 90.26°

p. 704, answer to Problem 11.10: (a) numerator is "

p. 704, answer to Problem 11.12: answer given to (c) is answer to (d)

p. 705, answer to Problem 11.20: (a) change "2 sin 2

p. 705, answer to Problem 11.31: add unit "V" to third answer

p. 705, answer to Problem 11.65: answer given is for (a)

p. 705, answer to Problem 12.10: numerator should be "8

p. 705, answer to Problem 12.14: should be answer to Problem 12.15

p. 706, answer to Problem 12.25: answer given is for (b)

p. 706, answer to Problem 12.27: 360

p. 706, answer to Problem 13.7: add terms "+ 0.424 sin 2¶

p. 707, answer to Problem 13.25: 0.637 - 0.212

p. 707, answer to Problem 14.21: (

Updated: 12-28-96